Base | Representation |
---|---|
bin | 111010011001100000001… |
… | …000111010110111111111 |
3 | 112012122112200222220202102 |
4 | 322121200020322313333 |
5 | 1011222323233434003 |
6 | 12311333130215315 |
7 | 562636444421435 |
oct | 72314010726777 |
9 | 15178480886672 |
10 | 4013112405503 |
11 | 1307a51370a33 |
12 | 54992728453b |
13 | 231586565666 |
14 | dc3429a8d55 |
15 | 6e5cc212588 |
hex | 3a66023adff |
4013112405503 has 2 divisors, whose sum is σ = 4013112405504. Its totient is φ = 4013112405502.
The previous prime is 4013112405481. The next prime is 4013112405517. The reversal of 4013112405503 is 3055042113104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4013112405503 - 26 = 4013112405439 is a prime.
It is a super-2 number, since 2×40131124055032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4013112405593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006556202751 + 2006556202752.
It is an arithmetic number, because the mean of its divisors is an integer number (2006556202752).
Almost surely, 24013112405503 is an apocalyptic number.
4013112405503 is a deficient number, since it is larger than the sum of its proper divisors (1).
4013112405503 is an equidigital number, since it uses as much as digits as its factorization.
4013112405503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 4013112405503 its reverse (3055042113104), we get a palindrome (7068154518607).
The spelling of 4013112405503 in words is "four trillion, thirteen billion, one hundred twelve million, four hundred five thousand, five hundred three".
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