Base | Representation |
---|---|
bin | 111010011001100000001… |
… | …000111010111001011001 |
3 | 112012122112200222220212202 |
4 | 322121200020322321121 |
5 | 1011222323233434333 |
6 | 12311333130215545 |
7 | 562636444421624 |
oct | 72314010727131 |
9 | 15178480886782 |
10 | 4013112405593 |
11 | 1307a51371005 |
12 | 5499272845b5 |
13 | 231586565705 |
14 | dc3429a8dbb |
15 | 6e5cc2125e8 |
hex | 3a66023ae59 |
4013112405593 has 2 divisors, whose sum is σ = 4013112405594. Its totient is φ = 4013112405592.
The previous prime is 4013112405521. The next prime is 4013112405623. The reversal of 4013112405593 is 3955042113104.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4003732870489 + 9379535104 = 2000933^2 + 96848^2 .
It is a cyclic number.
It is not a de Polignac number, because 4013112405593 - 212 = 4013112401497 is a prime.
It is a super-2 number, since 2×40131124055932 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4013112405503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006556202796 + 2006556202797.
It is an arithmetic number, because the mean of its divisors is an integer number (2006556202797).
Almost surely, 24013112405593 is an apocalyptic number.
It is an amenable number.
4013112405593 is a deficient number, since it is larger than the sum of its proper divisors (1).
4013112405593 is an equidigital number, since it uses as much as digits as its factorization.
4013112405593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 38.
Adding to 4013112405593 its reverse (3955042113104), we get a palindrome (7968154518697).
The spelling of 4013112405593 in words is "four trillion, thirteen billion, one hundred twelve million, four hundred five thousand, five hundred ninety-three".
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