Base | Representation |
---|---|
bin | 111010011001100001010… |
… | …000001111001111010111 |
3 | 112012122121000011202100112 |
4 | 322121201100033033113 |
5 | 1011222343030214033 |
6 | 12311335035033235 |
7 | 562640062345613 |
oct | 72314120171727 |
9 | 15178530152315 |
10 | 4013131101143 |
11 | 1307a6098027a |
12 | 54993159b81b |
13 | 23158a3b0178 |
14 | dc345274343 |
15 | 6e5cdba6c48 |
hex | 3a66140f3d7 |
4013131101143 has 4 divisors (see below), whose sum is σ = 4058222461920. Its totient is φ = 3968039740368.
The previous prime is 4013131101139. The next prime is 4013131101151. The reversal of 4013131101143 is 3411011313104.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4013131101143 - 22 = 4013131101139 is a prime.
It is a super-2 number, since 2×40131311011432 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4013131101113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22545680255 + ... + 22545680432.
It is an arithmetic number, because the mean of its divisors is an integer number (1014555615480).
Almost surely, 24013131101143 is an apocalyptic number.
4013131101143 is a deficient number, since it is larger than the sum of its proper divisors (45091360777).
4013131101143 is an equidigital number, since it uses as much as digits as its factorization.
4013131101143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45091360776.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 4013131101143 its reverse (3411011313104), we get a palindrome (7424142414247).
The spelling of 4013131101143 in words is "four trillion, thirteen billion, one hundred thirty-one million, one hundred one thousand, one hundred forty-three".
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