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401314200103 is a prime number
BaseRepresentation
bin1011101011100000011…
…00001011101000100111
31102100212021110122121201
411311300030023220213
523033342413400403
6504210004023331
740664640263125
oct5656014135047
91370767418551
10401314200103
11145218449393
126593b391b47
132bac79a883b
14155d093c915
15a68be9121d
hex5d7030ba27

401314200103 has 2 divisors, whose sum is σ = 401314200104. Its totient is φ = 401314200102.

The previous prime is 401314200083. The next prime is 401314200139. The reversal of 401314200103 is 301002413104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 401314200103 - 25 = 401314200071 is a prime.

It is a super-2 number, since 2×4013142001032 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (401314200163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200657100051 + 200657100052.

It is an arithmetic number, because the mean of its divisors is an integer number (200657100052).

Almost surely, 2401314200103 is an apocalyptic number.

401314200103 is a deficient number, since it is larger than the sum of its proper divisors (1).

401314200103 is an equidigital number, since it uses as much as digits as its factorization.

401314200103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 401314200103 its reverse (301002413104), we get a palindrome (702316613207).

The spelling of 401314200103 in words is "four hundred one billion, three hundred fourteen million, two hundred thousand, one hundred three".