40131736015751 has 2 divisors, whose sum is σ = 40131736015752. Its totient is φ = 40131736015750.

The previous prime is 40131736015729. The next prime is 40131736015753. The reversal of 40131736015751 is 15751063713104.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40131736015751 - 2¹⁸ = 40131735753607 is a prime.

It is a super-2 number, since 2×40131736015751² (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 40131736015753, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40131736015753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065868007875 + 20065868007876.

It is an arithmetic number, because the mean of its divisors is an integer number (20065868007876).

Almost surely, 2^{40131736015751} is an apocalyptic number.

40131736015751 is a deficient number, since it is larger than the sum of its proper divisors (1).

40131736015751 is an equidigital number, since it uses as much as digits as its factorization.

40131736015751 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 264600, while the sum is 44.

Adding to 40131736015751 its reverse (15751063713104), we get a palindrome (55882799728855).

The spelling of 40131736015751 in words is "forty trillion, one hundred thirty-one billion, seven hundred thirty-six million, fifteen thousand, seven hundred fifty-one".