40132111 has 4 divisors (see below), whose sum is σ = 40697424. Its totient is φ = 39566800.

The previous prime is 40132093. The next prime is 40132117. The reversal of 40132111 is 11123104.

40132111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40132111 - 2⁷ = 40131983 is a prime.

It is a super-2 number, since 2×40132111² = 3221172666632642, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40132091 and 40132100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40132117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 282550 + ... + 282691.

It is an arithmetic number, because the mean of its divisors is an integer number (10174356).

Almost surely, 2^40132111 is an apocalyptic number.

40132111 is a deficient number, since it is larger than the sum of its proper divisors (565313).

40132111 is an equidigital number, since it uses as much as digits as its factorization.

40132111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 565312.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 40132111 is about 6334.9910023614. The cubic root of 40132111 is about 342.3712866376.

Adding to 40132111 its reverse (11123104), we get a palindrome (51255215).

The spelling of 40132111 in words is "forty million, one hundred thirty-two thousand, one hundred eleven".