Base | Representation |
---|---|
bin | 111010011001100110100… |
… | …111101110011001010011 |
3 | 112012122211021121102010121 |
4 | 322121212213232121103 |
5 | 1011223034103103042 |
6 | 12311352013011111 |
7 | 562642234610635 |
oct | 72314647563123 |
9 | 15178737542117 |
10 | 4013221144147 |
11 | 1307aa7790986 |
12 | 549957783a97 |
13 | 2315a2c48857 |
14 | dc3531d2a55 |
15 | 6e5d6a41367 |
hex | 3a6669ee653 |
4013221144147 has 2 divisors, whose sum is σ = 4013221144148. Its totient is φ = 4013221144146.
The previous prime is 4013221144061. The next prime is 4013221144151. The reversal of 4013221144147 is 7414411223104.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4013221144147 is a prime.
It is a super-2 number, since 2×40132211441472 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4013221174147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006610572073 + 2006610572074.
It is an arithmetic number, because the mean of its divisors is an integer number (2006610572074).
Almost surely, 24013221144147 is an apocalyptic number.
4013221144147 is a deficient number, since it is larger than the sum of its proper divisors (1).
4013221144147 is an equidigital number, since it uses as much as digits as its factorization.
4013221144147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 34.
The spelling of 4013221144147 in words is "four trillion, thirteen billion, two hundred twenty-one million, one hundred forty-four thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •