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4013221144151 is a prime number
BaseRepresentation
bin111010011001100110100…
…111101110011001010111
3112012122211021121102010202
4322121212213232121113
51011223034103103101
612311352013011115
7562642234610642
oct72314647563127
915178737542122
104013221144151
111307aa779098a
12549957783a9b
132315a2c4885b
14dc3531d2a59
156e5d6a4136b
hex3a6669ee657

4013221144151 has 2 divisors, whose sum is σ = 4013221144152. Its totient is φ = 4013221144150.

The previous prime is 4013221144147. The next prime is 4013221144183. The reversal of 4013221144151 is 1514411223104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4013221144151 - 22 = 4013221144147 is a prime.

It is a super-2 number, since 2×40132211441512 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4013221144651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006610572075 + 2006610572076.

It is an arithmetic number, because the mean of its divisors is an integer number (2006610572076).

Almost surely, 24013221144151 is an apocalyptic number.

4013221144151 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013221144151 is an equidigital number, since it uses as much as digits as its factorization.

4013221144151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 4013221144151 its reverse (1514411223104), we get a palindrome (5527632367255).

The spelling of 4013221144151 in words is "four trillion, thirteen billion, two hundred twenty-one million, one hundred forty-four thousand, one hundred fifty-one".