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401335001 is a prime number
BaseRepresentation
bin10111111010111…
…110001011011001
31000222011221010022
4113322332023121
51310220210001
6103454000225
712642201614
oct2772761331
91028157108
10401335001
111965a7a21
12b24a6075
13651bb142
143b43117b
152537911b
hex17ebe2d9

401335001 has 2 divisors, whose sum is σ = 401335002. Its totient is φ = 401335000.

The previous prime is 401334971. The next prime is 401335003. The reversal of 401335001 is 100533104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 299809225 + 101525776 = 17315^2 + 10076^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-401335001 is a prime.

It is a super-2 number, since 2×4013350012 = 322139566055340002, which contains 22 as substring.

Together with 401335003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (401335003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200667500 + 200667501.

It is an arithmetic number, because the mean of its divisors is an integer number (200667501).

Almost surely, 2401335001 is an apocalyptic number.

It is an amenable number.

401335001 is a deficient number, since it is larger than the sum of its proper divisors (1).

401335001 is an equidigital number, since it uses as much as digits as its factorization.

401335001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 401335001 is about 20033.3472240662. The cubic root of 401335001 is about 737.6250871233.

Adding to 401335001 its reverse (100533104), we get a palindrome (501868105).

The spelling of 401335001 in words is "four hundred one million, three hundred thirty-five thousand, one".