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401341200031 is a prime number
BaseRepresentation
bin1011101011100011100…
…11001011011010011111
31102100221011021101120001
411311301303023122133
523033421321400111
6504212410435131
740665415625122
oct5656163133237
91370834241501
10401341200031
1114523170a882
1265948432aa7
132bb00470125
14155d436a3b9
15a68e5261c1
hex5d71ccb69f

401341200031 has 2 divisors, whose sum is σ = 401341200032. Its totient is φ = 401341200030.

The previous prime is 401341199989. The next prime is 401341200061. The reversal of 401341200031 is 130002143104.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 401341200031 - 217 = 401341068959 is a prime.

It is a super-2 number, since 2×4013412000312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 401341199981 and 401341200008.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (401341200061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200670600015 + 200670600016.

It is an arithmetic number, because the mean of its divisors is an integer number (200670600016).

Almost surely, 2401341200031 is an apocalyptic number.

401341200031 is a deficient number, since it is larger than the sum of its proper divisors (1).

401341200031 is an equidigital number, since it uses as much as digits as its factorization.

401341200031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 401341200031 its reverse (130002143104), we get a palindrome (531343343135).

The spelling of 401341200031 in words is "four hundred one billion, three hundred forty-one million, two hundred thousand, thirty-one".