401343531401 has 2 divisors, whose sum is σ = 401343531402. Its totient is φ = 401343531400.

The previous prime is 401343531367. The next prime is 401343531403. The reversal of 401343531401 is 104135343104.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 397373901376 + 3969630025 = 630376^2 + 63005^2 .

It is a cyclic number.

It is not a de Polignac number, because 401343531401 - 2³⁸ = 126465624457 is a prime.

It is a super-2 number, since 2×401343531401² (a number of 24 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 401343531403, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (401343531403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200671765700 + 200671765701.

It is an arithmetic number, because the mean of its divisors is an integer number (200671765701).

Almost surely, 2^401343531401 is an apocalyptic number.

It is an amenable number.

401343531401 is a deficient number, since it is larger than the sum of its proper divisors (1).

401343531401 is an equidigital number, since it uses as much as digits as its factorization.

401343531401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 401343531401 its reverse (104135343104), we get a palindrome (505478874505).

The spelling of 401343531401 in words is "four hundred one billion, three hundred forty-three million, five hundred thirty-one thousand, four hundred one".