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40135033551 = 370391900603
BaseRepresentation
bin100101011000001111…
…000000001011001111
310211121002010221201010
4211120033000023033
51124144032033201
630234321020303
72620404104424
oct453017001317
9124532127633
1040135033551
11160261a8818
127941184693
133a28041182
141d2a4bbd4b
15109d7abbd6
hex9583c02cf

40135033551 has 8 divisors (see below), whose sum is σ = 53521008640. Its totient is φ = 26752873752.

The previous prime is 40135033541. The next prime is 40135033607. The reversal of 40135033551 is 15533053104.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 40135033551 - 26 = 40135033487 is a prime.

It is a super-2 number, since 2×401350335512 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40135033541) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 929185 + ... + 971418.

It is an arithmetic number, because the mean of its divisors is an integer number (6690126080).

Almost surely, 240135033551 is an apocalyptic number.

40135033551 is a deficient number, since it is larger than the sum of its proper divisors (13385975089).

40135033551 is a wasteful number, since it uses less digits than its factorization.

40135033551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1907645.

The product of its (nonzero) digits is 13500, while the sum is 30.

Adding to 40135033551 its reverse (15533053104), we get a palindrome (55668086655).

The spelling of 40135033551 in words is "forty billion, one hundred thirty-five million, thirty-three thousand, five hundred fifty-one".

Divisors: 1 3 7039 21117 1900603 5701809 13378344517 40135033551