4014113433001 has 4 divisors (see below), whose sum is σ = 4587558209152. Its totient is φ = 3440668656852.

The previous prime is 4014113432999. The next prime is 4014113433049. The reversal of 4014113433001 is 1003343114104.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 4014113433001 - 2¹ = 4014113432999 is a prime.

It is a super-2 number, since 2×4014113433001² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4014113431001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 286722388065 + ... + 286722388078.

It is an arithmetic number, because the mean of its divisors is an integer number (1146889552288).

Almost surely, 2^{4014113433001} is an apocalyptic number.

It is an amenable number.

4014113433001 is a deficient number, since it is larger than the sum of its proper divisors (573444776151).

4014113433001 is an equidigital number, since it uses as much as digits as its factorization.

4014113433001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 573444776150.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4014113433001 its reverse (1003343114104), we get a palindrome (5017456547105).

The spelling of 4014113433001 in words is "four trillion, fourteen billion, one hundred thirteen million, four hundred thirty-three thousand, one".