Base | Representation |
---|---|
bin | 1011101011101101000… |
… | …11101110001001110111 |
3 | 1102101010201111101022112 |
4 | 11311312203232021313 |
5 | 23034102241042403 |
6 | 504224341521235 |
7 | 41000405330405 |
oct | 5656643561167 |
9 | 1371121441275 |
10 | 401421034103 |
11 | 145272788351 |
12 | 6596b11321b |
13 | 2bb13b72b1b |
14 | 15600bcc475 |
15 | a6965459d8 |
hex | 5d768ee277 |
401421034103 has 2 divisors, whose sum is σ = 401421034104. Its totient is φ = 401421034102.
The previous prime is 401421034099. The next prime is 401421034111. The reversal of 401421034103 is 301430124104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 401421034103 - 22 = 401421034099 is a prime.
It is a super-3 number, since 3×4014210341033 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (401421034303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200710517051 + 200710517052.
It is an arithmetic number, because the mean of its divisors is an integer number (200710517052).
Almost surely, 2401421034103 is an apocalyptic number.
401421034103 is a deficient number, since it is larger than the sum of its proper divisors (1).
401421034103 is an equidigital number, since it uses as much as digits as its factorization.
401421034103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 401421034103 its reverse (301430124104), we get a palindrome (702851158207).
Subtracting from 401421034103 its reverse (301430124104), we obtain a palindrome (99990909999).
The spelling of 401421034103 in words is "four hundred one billion, four hundred twenty-one million, thirty-four thousand, one hundred three".
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