Base | Representation |
---|---|
bin | 111010011010101111011… |
… | …110000010100100110011 |
3 | 112012202222110101111120121 |
4 | 322122233132002210303 |
5 | 1011233034443422011 |
6 | 12312113152551111 |
7 | 563014435251235 |
oct | 72325736024463 |
9 | 15182873344517 |
10 | 4014443342131 |
11 | 1308574679362 |
12 | 54a038b52497 |
13 | 231739212a21 |
14 | dc42b660255 |
15 | 6e658eb3e71 |
hex | 3a6af782933 |
4014443342131 has 2 divisors, whose sum is σ = 4014443342132. Its totient is φ = 4014443342130.
The previous prime is 4014443342093. The next prime is 4014443342141. The reversal of 4014443342131 is 1312433444104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4014443342131 - 27 = 4014443342003 is a prime.
It is a super-2 number, since 2×40144433421312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4014443342141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2007221671065 + 2007221671066.
It is an arithmetic number, because the mean of its divisors is an integer number (2007221671066).
Almost surely, 24014443342131 is an apocalyptic number.
4014443342131 is a deficient number, since it is larger than the sum of its proper divisors (1).
4014443342131 is an equidigital number, since it uses as much as digits as its factorization.
4014443342131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 4014443342131 its reverse (1312433444104), we get a palindrome (5326876786235).
The spelling of 4014443342131 in words is "four trillion, fourteen billion, four hundred forty-three million, three hundred forty-two thousand, one hundred thirty-one".
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