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40145500071121 is a prime number
BaseRepresentation
bin10010010000011000110100…
…10001010110010011010001
312021010212112220222110020111
421020030122101112103101
520230220441004233441
6221214331011441321
711312262626201554
oct1110143221262321
9167125486873214
1040145500071121
111187867a221035
1246045728b6241
1319529207968c3
149cb0a437c69b
15499423724081
hex24831a4564d1

40145500071121 has 2 divisors, whose sum is σ = 40145500071122. Its totient is φ = 40145500071120.

The previous prime is 40145500071119. The next prime is 40145500071197. The reversal of 40145500071121 is 12117000554104.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20503363588096 + 19642136483025 = 4528064^2 + 4431945^2 .

It is a cyclic number.

It is not a de Polignac number, because 40145500071121 - 21 = 40145500071119 is a prime.

It is a super-2 number, since 2×401455000711212 (a number of 28 digits) contains 22 as substring.

Together with 40145500071119, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (40145500071101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20072750035560 + 20072750035561.

It is an arithmetic number, because the mean of its divisors is an integer number (20072750035561).

Almost surely, 240145500071121 is an apocalyptic number.

It is an amenable number.

40145500071121 is a deficient number, since it is larger than the sum of its proper divisors (1).

40145500071121 is an equidigital number, since it uses as much as digits as its factorization.

40145500071121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5600, while the sum is 31.

The spelling of 40145500071121 in words is "forty trillion, one hundred forty-five billion, five hundred million, seventy-one thousand, one hundred twenty-one".