Base | Representation |
---|---|
bin | 111010011011000001010… |
… | …000101011001101110111 |
3 | 112012210202021001011212020 |
4 | 322123001100223031313 |
5 | 1011234142402002341 |
6 | 12312202534324223 |
7 | 563025021324633 |
oct | 72330120531567 |
9 | 15183667034766 |
10 | 4014741828471 |
11 | 1308708109590 |
12 | 54a100ab9673 |
13 | 23178600086a |
14 | dc45915bdc3 |
15 | 6e6752c4566 |
hex | 3a6c142b377 |
4014741828471 has 64 divisors (see below), whose sum is σ = 6074429068800. Its totient is φ = 2337728140800.
The previous prime is 4014741828469. The next prime is 4014741828491. The reversal of 4014741828471 is 1748281474104.
4014741828471 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4014741828471 - 21 = 4014741828469 is a prime.
It is a super-3 number, since 3×40147418284713 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4014741828491) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 18538765 + ... + 18754073.
It is an arithmetic number, because the mean of its divisors is an integer number (94912954200).
Almost surely, 24014741828471 is an apocalyptic number.
4014741828471 is a deficient number, since it is larger than the sum of its proper divisors (2059687240329).
4014741828471 is a wasteful number, since it uses less digits than its factorization.
4014741828471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 215600.
The product of its (nonzero) digits is 1605632, while the sum is 51.
The spelling of 4014741828471 in words is "four trillion, fourteen billion, seven hundred forty-one million, eight hundred twenty-eight thousand, four hundred seventy-one".
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