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402000113 is a prime number
BaseRepresentation
bin10111111101100…
…000100011110001
31001000102201111002
4113331200203301
51310403000423
6103520131345
712650641664
oct2775404361
91030381432
10402000113
11196a116a9
12b2766b55
1365391ab8
143b5656db
152545b228
hex17f608f1

402000113 has 2 divisors, whose sum is σ = 402000114. Its totient is φ = 402000112.

The previous prime is 402000089. The next prime is 402000127. The reversal of 402000113 is 311000204.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 290634304 + 111365809 = 17048^2 + 10553^2 .

It is a cyclic number.

It is not a de Polignac number, because 402000113 - 212 = 401996017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 402000094 and 402000103.

It is not a weakly prime, because it can be changed into another prime (402000013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201000056 + 201000057.

It is an arithmetic number, because the mean of its divisors is an integer number (201000057).

Almost surely, 2402000113 is an apocalyptic number.

It is an amenable number.

402000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

402000113 is an equidigital number, since it uses as much as digits as its factorization.

402000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 11.

The square root of 402000113 is about 20049.9404737271. The cubic root of 402000113 is about 738.0323383621.

Adding to 402000113 its reverse (311000204), we get a palindrome (713000317).

Subtracting from 402000113 its reverse (311000204), we obtain a palindrome (90999909).

The spelling of 402000113 in words is "four hundred two million, one hundred thirteen", and thus it is an aban number.