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402013442021 is a prime number
BaseRepresentation
bin1011101100110011101…
…11100100111111100101
31102102200000012211012112
411312121313210333211
523041310420121041
6504403223130405
741021160606242
oct5663167447745
91372600184175
10402013442021
11145547120174
1265ab55a3a05
132bba9810b59
141565975a5c9
15a6cd563deb
hex5d99de4fe5

402013442021 has 2 divisors, whose sum is σ = 402013442022. Its totient is φ = 402013442020.

The previous prime is 402013442011. The next prime is 402013442053. The reversal of 402013442021 is 120244310204.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 209631201025 + 192382240996 = 457855^2 + 438614^2 .

It is a cyclic number.

It is not a de Polignac number, because 402013442021 - 230 = 400939700197 is a prime.

It is a super-2 number, since 2×4020134420212 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (402013442011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201006721010 + 201006721011.

It is an arithmetic number, because the mean of its divisors is an integer number (201006721011).

Almost surely, 2402013442021 is an apocalyptic number.

It is an amenable number.

402013442021 is a deficient number, since it is larger than the sum of its proper divisors (1).

402013442021 is an equidigital number, since it uses as much as digits as its factorization.

402013442021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 23.

Adding to 402013442021 its reverse (120244310204), we get a palindrome (522257752225).

The spelling of 402013442021 in words is "four hundred two billion, thirteen million, four hundred forty-two thousand, twenty-one".