Base | Representation |
---|---|
bin | 1011101100110011101… |
… | …11100100111111100101 |
3 | 1102102200000012211012112 |
4 | 11312121313210333211 |
5 | 23041310420121041 |
6 | 504403223130405 |
7 | 41021160606242 |
oct | 5663167447745 |
9 | 1372600184175 |
10 | 402013442021 |
11 | 145547120174 |
12 | 65ab55a3a05 |
13 | 2bba9810b59 |
14 | 1565975a5c9 |
15 | a6cd563deb |
hex | 5d99de4fe5 |
402013442021 has 2 divisors, whose sum is σ = 402013442022. Its totient is φ = 402013442020.
The previous prime is 402013442011. The next prime is 402013442053. The reversal of 402013442021 is 120244310204.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 209631201025 + 192382240996 = 457855^2 + 438614^2 .
It is a cyclic number.
It is not a de Polignac number, because 402013442021 - 230 = 400939700197 is a prime.
It is a super-2 number, since 2×4020134420212 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (402013442011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201006721010 + 201006721011.
It is an arithmetic number, because the mean of its divisors is an integer number (201006721011).
Almost surely, 2402013442021 is an apocalyptic number.
It is an amenable number.
402013442021 is a deficient number, since it is larger than the sum of its proper divisors (1).
402013442021 is an equidigital number, since it uses as much as digits as its factorization.
402013442021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 402013442021 its reverse (120244310204), we get a palindrome (522257752225).
The spelling of 402013442021 in words is "four hundred two billion, thirteen million, four hundred forty-two thousand, twenty-one".
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