Base | Representation |
---|---|
bin | 111010100001000010110… |
… | …100011010000000000101 |
3 | 112020102110001211211210112 |
4 | 322201002310122000011 |
5 | 1011340414332021201 |
6 | 12315152451002405 |
7 | 563344225426661 |
oct | 72410264320005 |
9 | 15212401754715 |
10 | 4021210423301 |
11 | 13104274a6625 |
12 | 54b407299405 |
13 | 2322771a6c76 |
14 | dc8b02a98a1 |
15 | 6e9031200bb |
hex | 3a842d1a005 |
4021210423301 has 2 divisors, whose sum is σ = 4021210423302. Its totient is φ = 4021210423300.
The previous prime is 4021210423249. The next prime is 4021210423337. The reversal of 4021210423301 is 1033240121204.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2366966865025 + 1654243558276 = 1538495^2 + 1286174^2 .
It is a cyclic number.
It is not a de Polignac number, because 4021210423301 - 238 = 3746332516357 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4021210423201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010605211650 + 2010605211651.
It is an arithmetic number, because the mean of its divisors is an integer number (2010605211651).
Almost surely, 24021210423301 is an apocalyptic number.
It is an amenable number.
4021210423301 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021210423301 is an equidigital number, since it uses as much as digits as its factorization.
4021210423301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 4021210423301 its reverse (1033240121204), we get a palindrome (5054450544505).
The spelling of 4021210423301 in words is "four trillion, twenty-one billion, two hundred ten million, four hundred twenty-three thousand, three hundred one".
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