Base | Representation |
---|---|
bin | 10010010010010100111011… |
… | …11010010000110010110001 |
3 | 12021101020112200211010010012 |
4 | 21021022131322100302301 |
5 | 20232313422034334301 |
6 | 221305110545144305 |
7 | 11320142100604646 |
oct | 1111123572206261 |
9 | 167336480733105 |
10 | 40212133121201 |
11 | 118a3962900868 |
12 | 461546a02b095 |
13 | 1958cac4ba7a2 |
14 | 9d03c5b4bdcd |
15 | 49b023459ebb |
hex | 24929de90cb1 |
40212133121201 has 2 divisors, whose sum is σ = 40212133121202. Its totient is φ = 40212133121200.
The previous prime is 40212133121161. The next prime is 40212133121203. The reversal of 40212133121201 is 10212133121204.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29320654671025 + 10891478450176 = 5414855^2 + 3300224^2 .
It is a cyclic number.
It is not a de Polignac number, because 40212133121201 - 210 = 40212133120177 is a prime.
Together with 40212133121203, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (40212133121203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20106066560600 + 20106066560601.
It is an arithmetic number, because the mean of its divisors is an integer number (20106066560601).
Almost surely, 240212133121201 is an apocalyptic number.
It is an amenable number.
40212133121201 is a deficient number, since it is larger than the sum of its proper divisors (1).
40212133121201 is an equidigital number, since it uses as much as digits as its factorization.
40212133121201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 40212133121201 its reverse (10212133121204), we get a palindrome (50424266242405).
The spelling of 40212133121201 in words is "forty trillion, two hundred twelve billion, one hundred thirty-three million, one hundred twenty-one thousand, two hundred one".
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