Base | Representation |
---|---|
bin | 111010100001000100110… |
… | …010010010001010011101 |
3 | 112020102112100221022121011 |
4 | 322201010302102022131 |
5 | 1011341001303440331 |
6 | 12315200030135221 |
7 | 563345106053116 |
oct | 72410462221235 |
9 | 15212470838534 |
10 | 4021243421341 |
11 | 1310444094533 |
12 | 54b416351511 |
13 | 232280c8b733 |
14 | dc8b481920d |
15 | 6e905e8c3b1 |
hex | 3a844c9229d |
4021243421341 has 2 divisors, whose sum is σ = 4021243421342. Its totient is φ = 4021243421340.
The previous prime is 4021243421323. The next prime is 4021243421353. The reversal of 4021243421341 is 1431243421204.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3456453595716 + 564789825625 = 1859154^2 + 751525^2 .
It is a cyclic number.
It is not a de Polignac number, because 4021243421341 - 213 = 4021243413149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4021243421641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010621710670 + 2010621710671.
It is an arithmetic number, because the mean of its divisors is an integer number (2010621710671).
Almost surely, 24021243421341 is an apocalyptic number.
It is an amenable number.
4021243421341 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021243421341 is an equidigital number, since it uses as much as digits as its factorization.
4021243421341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 4021243421341 its reverse (1431243421204), we get a palindrome (5452486842545).
The spelling of 4021243421341 in words is "four trillion, twenty-one billion, two hundred forty-three million, four hundred twenty-one thousand, three hundred forty-one".
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