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402144444341 is a prime number
BaseRepresentation
bin1011101101000011010…
…11010011111110110101
31102110000010201102121022
411312201223103332311
523042042434204331
6504424223030525
741024341243223
oct5664153237665
91373003642538
10402144444341
11145604067152
1265b3143b445
132bbca9ba913
141566ccdbb13
15a6d9cde67b
hex5da1ad3fb5

402144444341 has 2 divisors, whose sum is σ = 402144444342. Its totient is φ = 402144444340.

The previous prime is 402144444301. The next prime is 402144444343. The reversal of 402144444341 is 143444441204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 255382665316 + 146761779025 = 505354^2 + 383095^2 .

It is a cyclic number.

It is not a de Polignac number, because 402144444341 - 238 = 127266537397 is a prime.

It is a super-3 number, since 3×4021444443413 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 402144444343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (402144444343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201072222170 + 201072222171.

It is an arithmetic number, because the mean of its divisors is an integer number (201072222171).

Almost surely, 2402144444341 is an apocalyptic number.

It is an amenable number.

402144444341 is a deficient number, since it is larger than the sum of its proper divisors (1).

402144444341 is an equidigital number, since it uses as much as digits as its factorization.

402144444341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 98304, while the sum is 35.

Adding to 402144444341 its reverse (143444441204), we get a palindrome (545588885545).

The spelling of 402144444341 in words is "four hundred two billion, one hundred forty-four million, four hundred forty-four thousand, three hundred forty-one".