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402213243431 is a prime number
BaseRepresentation
bin1011101101001011100…
…01110000101000100111
31102110011221011210012202
411312211301300220213
523042213042242211
6504435121405115
741026135105526
oct5664561605047
91373157153182
10402213243431
111456399879aa
1265b5049979b
132bc0c02893c
14156780ca4bd
15a6e0d7e53b
hex5da5c70a27

402213243431 has 2 divisors, whose sum is σ = 402213243432. Its totient is φ = 402213243430.

The previous prime is 402213243407. The next prime is 402213243433. The reversal of 402213243431 is 134342312204.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-402213243431 is a prime.

It is a super-2 number, since 2×4022132434312 (a number of 24 digits) contains 22 as substring.

Together with 402213243433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 402213243394 and 402213243403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (402213243433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201106621715 + 201106621716.

It is an arithmetic number, because the mean of its divisors is an integer number (201106621716).

Almost surely, 2402213243431 is an apocalyptic number.

402213243431 is a deficient number, since it is larger than the sum of its proper divisors (1).

402213243431 is an equidigital number, since it uses as much as digits as its factorization.

402213243431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 402213243431 its reverse (134342312204), we get a palindrome (536555555635).

The spelling of 402213243431 in words is "four hundred two billion, two hundred thirteen million, two hundred forty-three thousand, four hundred thirty-one".