Base | Representation |
---|---|
bin | 111010100010000011110… |
… | …110010001010100000111 |
3 | 112020112021002202210001211 |
4 | 322202003312101110013 |
5 | 1011400133131243142 |
6 | 12315453023032251 |
7 | 563413244021404 |
oct | 72420366212407 |
9 | 15215232683054 |
10 | 4022301431047 |
11 | 1310937329919 |
12 | 54b67073b687 |
13 | 2323bc229993 |
14 | dc9751472ab |
15 | 6e968ccb917 |
hex | 3a883d91507 |
4022301431047 has 2 divisors, whose sum is σ = 4022301431048. Its totient is φ = 4022301431046.
The previous prime is 4022301431003. The next prime is 4022301431069. The reversal of 4022301431047 is 7401341032204.
4022301431047 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4022301431047 - 231 = 4020153947399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4022301431147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011150715523 + 2011150715524.
It is an arithmetic number, because the mean of its divisors is an integer number (2011150715524).
Almost surely, 24022301431047 is an apocalyptic number.
4022301431047 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022301431047 is an equidigital number, since it uses as much as digits as its factorization.
4022301431047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
The spelling of 4022301431047 in words is "four trillion, twenty-two billion, three hundred one million, four hundred thirty-one thousand, forty-seven".
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