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4023014213461 is a prime number
BaseRepresentation
bin111010100010101110010…
…101010100011101010101
3112020121002202222212201111
4322202232111110131111
51011403113114312321
612320051444255021
7563440020411265
oct72425625243525
915217082885644
104023014213461
1113111727098a1
1254b82b3a1471
132324a3ac3219
14dca01a8b7a5
156e9ab6765e1
hex3a8ae554755

4023014213461 has 2 divisors, whose sum is σ = 4023014213462. Its totient is φ = 4023014213460.

The previous prime is 4023014213459. The next prime is 4023014213473. The reversal of 4023014213461 is 1643124103204.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2689947691236 + 1333066522225 = 1640106^2 + 1154585^2 .

It is a cyclic number.

It is not a de Polignac number, because 4023014213461 - 21 = 4023014213459 is a prime.

It is a super-3 number, since 3×40230142134613 (a number of 39 digits) contains 333 as substring.

Together with 4023014213459, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4023014223461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011507106730 + 2011507106731.

It is an arithmetic number, because the mean of its divisors is an integer number (2011507106731).

Almost surely, 24023014213461 is an apocalyptic number.

It is an amenable number.

4023014213461 is a deficient number, since it is larger than the sum of its proper divisors (1).

4023014213461 is an equidigital number, since it uses as much as digits as its factorization.

4023014213461 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 4023014213461 its reverse (1643124103204), we get a palindrome (5666138316665).

The spelling of 4023014213461 in words is "four trillion, twenty-three billion, fourteen million, two hundred thirteen thousand, four hundred sixty-one".