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40231233213203 = 328043122640121
BaseRepresentation
bin10010010010111000100000…
…10111010101001100010011
312021110001211211000022200002
421021130100113111030103
520233122031200310303
6221321550130320215
711321416314655244
oct1111342027251423
9167401754008602
1040231233213203
1111900a7436066a
1246190ba72906b
13195aa34601886
149d12b86dcccb
1549b7901b6788
hex2497105d5313

40231233213203 has 4 divisors (see below), whose sum is σ = 40231356181368. Its totient is φ = 40231110245040.

The previous prime is 40231233213167. The next prime is 40231233213211. The reversal of 40231233213203 is 30231233213204.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40231233213203 - 212 = 40231233209107 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (40231233233203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60992018 + ... + 61648103.

It is an arithmetic number, because the mean of its divisors is an integer number (10057839045342).

Almost surely, 240231233213203 is an apocalyptic number.

40231233213203 is a deficient number, since it is larger than the sum of its proper divisors (122968165).

40231233213203 is a wasteful number, since it uses less digits than its factorization.

40231233213203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122968164.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 40231233213203 its reverse (30231233213204), we get a palindrome (70462466426407).

Subtracting from 40231233213203 its reverse (30231233213204), we obtain a palindrome (9999999999999).

The spelling of 40231233213203 in words is "forty trillion, two hundred thirty-one billion, two hundred thirty-three million, two hundred thirteen thousand, two hundred three".

Divisors: 1 328043 122640121 40231233213203