402314113 has 4 divisors (see below), whose sum is σ = 423488560. Its totient is φ = 381139668.

The previous prime is 402314111. The next prime is 402314123. The reversal of 402314113 is 311413204.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 402314113 - 2¹ = 402314111 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 21174427 = 402314113 / (4 + 0 + 2 + 3 + 1 + 4 + 1 + 1 + 3).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (402314111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10587195 + ... + 10587232.

It is an arithmetic number, because the mean of its divisors is an integer number (105872140).

Almost surely, 2^402314113 is an apocalyptic number.

It is an amenable number.

402314113 is a deficient number, since it is larger than the sum of its proper divisors (21174447).

402314113 is a wasteful number, since it uses less digits than its factorization.

402314113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21174446.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 402314113 is about 20057.7693924324. The cubic root of 402314113 is about 738.2244459722.

Adding to 402314113 its reverse (311413204), we get a palindrome (713727317).

Subtracting from 402314113 its reverse (311413204), we obtain a palindrome (90900909).

It can be divided in two parts, 40231 and 4113, that added together give a palindrome (44344).

The spelling of 402314113 in words is "four hundred two million, three hundred fourteen thousand, one hundred thirteen".