Base | Representation |
---|---|
bin | 111010100011111101000… |
… | …001011100100110111111 |
3 | 112020201111210011111201112 |
4 | 322203331001130212333 |
5 | 1011413314101412111 |
6 | 12320430444432235 |
7 | 563514521013344 |
oct | 72437501344677 |
9 | 15221453144645 |
10 | 4024334404031 |
11 | 131178a947587 |
12 | 54bb3954867b |
13 | 23265447a286 |
14 | dcac91467cb |
15 | 6ea37503e8b |
hex | 3a8fd05c9bf |
4024334404031 has 2 divisors, whose sum is σ = 4024334404032. Its totient is φ = 4024334404030.
The previous prime is 4024334403997. The next prime is 4024334404033. The reversal of 4024334404031 is 1304044334204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4024334404031 - 210 = 4024334403007 is a prime.
It is a super-2 number, since 2×40243344040312 (a number of 26 digits) contains 22 as substring.
Together with 4024334404033, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4024334404033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2012167202015 + 2012167202016.
It is an arithmetic number, because the mean of its divisors is an integer number (2012167202016).
Almost surely, 24024334404031 is an apocalyptic number.
4024334404031 is a deficient number, since it is larger than the sum of its proper divisors (1).
4024334404031 is an equidigital number, since it uses as much as digits as its factorization.
4024334404031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 4024334404031 its reverse (1304044334204), we get a palindrome (5328378738235).
The spelling of 4024334404031 in words is "four trillion, twenty-four billion, three hundred thirty-four million, four hundred four thousand, thirty-one".
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