40253523112053 has 24 divisors (see below), whose sum is σ = 61566855105600. Its totient is φ = 25256028115584.

The previous prime is 40253523112013. The next prime is 40253523112057. The reversal of 40253523112053 is 35021132535204.

40253523112053 is a `hidden beast` number, since 4 + 0 + 2 + 5 + 3 + 523 + 1 + 120 + 5 + 3 = 666.

It is not a de Polignac number, because 40253523112053 - 2⁸ = 40253523111797 is a prime.

It is a super-2 number, since 2×40253523112053² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40253523111999 and 40253523112017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40253523112057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2065513 + ... + 9207246.

It is an arithmetic number, because the mean of its divisors is an integer number (2565285629400).

Almost surely, 2^{40253523112053} is an apocalyptic number.

It is an amenable number.

40253523112053 is a deficient number, since it is larger than the sum of its proper divisors (21313331993547).

40253523112053 is a wasteful number, since it uses less digits than its factorization.

40253523112053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11296121 (or 11296118 counting only the distinct ones).

The product of its (nonzero) digits is 108000, while the sum is 36.

Adding to 40253523112053 its reverse (35021132535204), we get a palindrome (75274655647257).

The spelling of 40253523112053 in words is "forty trillion, two hundred fifty-three billion, five hundred twenty-three million, one hundred twelve thousand, fifty-three".