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40254113996101 is a prime number
BaseRepresentation
bin10010010011100011001000…
…01010100101110101000101
312021112020220102020112010201
421021301210022211311011
520234010411140333401
6221340252405050501
711323156320264145
oct1111614412456505
9167466812215121
1040254113996101
111190a745a234a5
1246216253b6a31
13195cc3ca7c275
149d2449436925
1549c17dcc7b01
hex249c642a5d45

40254113996101 has 2 divisors, whose sum is σ = 40254113996102. Its totient is φ = 40254113996100.

The previous prime is 40254113996099. The next prime is 40254113996111. The reversal of 40254113996101 is 10169931145204.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22737629023201 + 17516484972900 = 4768399^2 + 4185270^2 .

It is a cyclic number.

It is not a de Polignac number, because 40254113996101 - 21 = 40254113996099 is a prime.

It is a super-2 number, since 2×402541139961012 (a number of 28 digits) contains 22 as substring.

Together with 40254113996099, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40254113996111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20127056998050 + 20127056998051.

It is an arithmetic number, because the mean of its divisors is an integer number (20127056998051).

Almost surely, 240254113996101 is an apocalyptic number.

It is an amenable number.

40254113996101 is a deficient number, since it is larger than the sum of its proper divisors (1).

40254113996101 is an equidigital number, since it uses as much as digits as its factorization.

40254113996101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 233280, while the sum is 46.

The spelling of 40254113996101 in words is "forty trillion, two hundred fifty-four billion, one hundred thirteen million, nine hundred ninety-six thousand, one hundred one".