40254281 has 2 divisors, whose sum is σ = 40254282. Its totient is φ = 40254280.

The previous prime is 40254271. The next prime is 40254341. The reversal of 40254281 is 18245204.

It is a happy number.

40254281 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39488656 + 765625 = 6284^2 + 875^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-40254281 is a prime.

It is a super-2 number, since 2×40254281² = 3240814277653922, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 40254281.

It is not a weakly prime, because it can be changed into another prime (40254211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20127140 + 20127141.

It is an arithmetic number, because the mean of its divisors is an integer number (20127141).

Almost surely, 2^40254281 is an apocalyptic number.

It is an amenable number.

40254281 is a deficient number, since it is larger than the sum of its proper divisors (1).

40254281 is an equidigital number, since it uses as much as digits as its factorization.

40254281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2560, while the sum is 26.

The square root of 40254281 is about 6344.6261513189. The cubic root of 40254281 is about 342.7183497664.

Adding to 40254281 its reverse (18245204), we get a palindrome (58499485).

The spelling of 40254281 in words is "forty million, two hundred fifty-four thousand, two hundred eighty-one".