Base | Representation |
---|---|
bin | 10010010101010001000011… |
… | …10111000001101110000111 |
3 | 12021201220020102100201020010 |
4 | 21022220201313001232013 |
5 | 20240442243031111401 |
6 | 221423332522441303 |
7 | 11330345653432365 |
oct | 1112504167015607 |
9 | 167656212321203 |
10 | 40313131113351 |
11 | 11932780609168 |
12 | 4630b56063233 |
13 | 19656869b3515 |
14 | 9d5247556635 |
15 | 49d9850caed6 |
hex | 24aa21dc1b87 |
40313131113351 has 8 divisors (see below), whose sum is σ = 53809843509504. Its totient is φ = 26845919729720.
The previous prime is 40313131113349. The next prime is 40313131113361. The reversal of 40313131113351 is 15331113131304.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 40313131113351 - 21 = 40313131113349 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40313131113301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7375249941 + ... + 7375255406.
It is an arithmetic number, because the mean of its divisors is an integer number (6726230438688).
Almost surely, 240313131113351 is an apocalyptic number.
40313131113351 is a deficient number, since it is larger than the sum of its proper divisors (13496712396153).
40313131113351 is a wasteful number, since it uses less digits than its factorization.
40313131113351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14750506261.
The product of its (nonzero) digits is 4860, while the sum is 30.
Adding to 40313131113351 its reverse (15331113131304), we get a palindrome (55644244244655).
The spelling of 40313131113351 in words is "forty trillion, three hundred thirteen billion, one hundred thirty-one million, one hundred thirteen thousand, three hundred fifty-one".
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