403140310104231 has 64 divisors (see below), whose sum is σ = 698880283545600. Its totient is φ = 224884887383808.

The previous prime is 403140310104179. The next prime is 403140310104241. The reversal of 403140310104231 is 132401013041304.

403140310104231 is a `hidden beast` number, since 4 + 0 + 3 + 1 + 403 + 10 + 10 + 4 + 231 = 666.

It is not a de Polignac number, because 403140310104231 - 2²³ = 403140301715623 is a prime.

It is a super-2 number, since 2×403140310104231² (a number of 30 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 403140310104195 and 403140310104204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (403140310104241) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 54877870 + ... + 61788843.

It is an arithmetic number, because the mean of its divisors is an integer number (10920004430400).

Almost surely, 2^{403140310104231} is an apocalyptic number.

403140310104231 is a deficient number, since it is larger than the sum of its proper divisors (295739973441369).

403140310104231 is a wasteful number, since it uses less digits than its factorization.

403140310104231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 116667165 (or 116667159 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 403140310104231 its reverse (132401013041304), we get a palindrome (535541323145535).

The spelling of 403140310104231 in words is "four hundred three trillion, one hundred forty billion, three hundred ten million, one hundred four thousand, two hundred thirty-one".