Base | Representation |
---|---|
bin | 111010101011011110011… |
… | …111011111100000101101 |
3 | 112021111100201211001110000 |
4 | 322223132133133200231 |
5 | 1012031340000334013 |
6 | 12324244202134513 |
7 | 564221634331104 |
oct | 72533637374055 |
9 | 15244321731400 |
10 | 4032412121133 |
11 | 1315155576a40 |
12 | 5516127b1439 |
13 | 233340b31636 |
14 | dd253c8103b |
15 | 6ed5b751973 |
hex | 3aade7df82d |
4032412121133 has 40 divisors (see below), whose sum is σ = 6572062797696. Its totient is φ = 2443616683200.
The previous prime is 4032412121069. The next prime is 4032412121159. The reversal of 4032412121133 is 3311212142304.
4032412121133 is a `hidden beast` number, since 4 + 0 + 3 + 2 + 412 + 1 + 211 + 33 = 666.
It is not a de Polignac number, because 4032412121133 - 26 = 4032412121069 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 4032412121097 and 4032412121106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4032812121133) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 7988860 + ... + 8478602.
Almost surely, 24032412121133 is an apocalyptic number.
It is an amenable number.
4032412121133 is a deficient number, since it is larger than the sum of its proper divisors (2539650676563).
4032412121133 is a wasteful number, since it uses less digits than its factorization.
4032412121133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 499007 (or 498998 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 4032412121133 its reverse (3311212142304), we get a palindrome (7343624263437).
The spelling of 4032412121133 in words is "four trillion, thirty-two billion, four hundred twelve million, one hundred twenty-one thousand, one hundred thirty-three".
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