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40325189981 is a prime number
BaseRepresentation
bin100101100011100100…
…011001000101011101
310212002022221220021212
4211203210121011131
51130041222034411
630305232434205
72625203313356
oct454344310535
9125068856255
1040325189981
111611357809a
1279949a8965
133a5855cb7b
141d4785ad2d
1510b031e68b
hex96391915d

40325189981 has 2 divisors, whose sum is σ = 40325189982. Its totient is φ = 40325189980.

The previous prime is 40325189953. The next prime is 40325190001. The reversal of 40325189981 is 18998152304.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31237381081 + 9087808900 = 176741^2 + 95330^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40325189981 is a prime.

It is a super-2 number, since 2×403251899812 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40325189911) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20162594990 + 20162594991.

It is an arithmetic number, because the mean of its divisors is an integer number (20162594991).

Almost surely, 240325189981 is an apocalyptic number.

It is an amenable number.

40325189981 is a deficient number, since it is larger than the sum of its proper divisors (1).

40325189981 is an equidigital number, since it uses as much as digits as its factorization.

40325189981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 622080, while the sum is 50.

The spelling of 40325189981 in words is "forty billion, three hundred twenty-five million, one hundred eighty-nine thousand, nine hundred eighty-one".