403253551342511 has 2 divisors, whose sum is σ = 403253551342512. Its totient is φ = 403253551342510.

The previous prime is 403253551342507. The next prime is 403253551342513. The reversal of 403253551342511 is 115243155352304.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 403253551342511 - 2² = 403253551342507 is a prime.

It is a super-2 number, since 2×403253551342511² (a number of 30 digits) contains 22 as substring.

Together with 403253551342513, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (403253551342513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201626775671255 + 201626775671256.

It is an arithmetic number, because the mean of its divisors is an integer number (201626775671256).

Almost surely, 2^{403253551342511} is an apocalyptic number.

403253551342511 is a deficient number, since it is larger than the sum of its proper divisors (1).

403253551342511 is an equidigital number, since it uses as much as digits as its factorization.

403253551342511 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080000, while the sum is 44.

The spelling of 403253551342511 in words is "four hundred three trillion, two hundred fifty-three billion, five hundred fifty-one million, three hundred forty-two thousand, five hundred eleven".