Base | Representation |
---|---|
bin | 1111000001100100… |
… | …0110111101010101 |
3 | 101102002000102020102 |
4 | 3300121012331111 |
5 | 31224434121231 |
6 | 1504111343445 |
7 | 201641621453 |
oct | 36031067525 |
9 | 11362012212 |
10 | 4033113941 |
11 | 178a65121a |
12 | 946821b85 |
13 | 4c3746b6c |
14 | 2a38d39d3 |
15 | 189116acb |
hex | f0646f55 |
4033113941 has 2 divisors, whose sum is σ = 4033113942. Its totient is φ = 4033113940.
The previous prime is 4033113913. The next prime is 4033113947. The reversal of 4033113941 is 1493113304.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2366433316 + 1666680625 = 48646^2 + 40825^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4033113941 is a prime.
It is a super-2 number, since 2×40331139412 = 32532016122177102962, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4033113947) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016556970 + 2016556971.
It is an arithmetic number, because the mean of its divisors is an integer number (2016556971).
Almost surely, 24033113941 is an apocalyptic number.
It is an amenable number.
4033113941 is a deficient number, since it is larger than the sum of its proper divisors (1).
4033113941 is an equidigital number, since it uses as much as digits as its factorization.
4033113941 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 29.
The square root of 4033113941 is about 63506.8023206963. The cubic root of 4033113941 is about 1591.7694448926.
The spelling of 4033113941 in words is "four billion, thirty-three million, one hundred thirteen thousand, nine hundred forty-one".
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