Base | Representation |
---|---|
bin | 111010101101000101100… |
… | …111010001000000101101 |
3 | 112021122211022021210010202 |
4 | 322231011213101000231 |
5 | 1012043410401242031 |
6 | 12325132004043245 |
7 | 564312543011156 |
oct | 72550547210055 |
9 | 15248738253122 |
10 | 4034142212141 |
11 | 1315963121a18 |
12 | 551a16093525 |
13 | 2335583b5422 |
14 | dd37995a92d |
15 | 6ee0d59b2cb |
hex | 3ab459d102d |
4034142212141 has 2 divisors, whose sum is σ = 4034142212142. Its totient is φ = 4034142212140.
The previous prime is 4034142212119. The next prime is 4034142212143. The reversal of 4034142212141 is 1412122414304.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3816103645225 + 218038566916 = 1953485^2 + 466946^2 .
It is a cyclic number.
It is not a de Polignac number, because 4034142212141 - 226 = 4034075103277 is a prime.
Together with 4034142212143, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4034142212143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2017071106070 + 2017071106071.
It is an arithmetic number, because the mean of its divisors is an integer number (2017071106071).
Almost surely, 24034142212141 is an apocalyptic number.
It is an amenable number.
4034142212141 is a deficient number, since it is larger than the sum of its proper divisors (1).
4034142212141 is an equidigital number, since it uses as much as digits as its factorization.
4034142212141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 4034142212141 its reverse (1412122414304), we get a palindrome (5446264626445).
The spelling of 4034142212141 in words is "four trillion, thirty-four billion, one hundred forty-two million, two hundred twelve thousand, one hundred forty-one".
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