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40375193265989 is a prime number
BaseRepresentation
bin10010010111000100101010…
…00011010110011101000101
312021221211102122020201120222
421023202111003112131011
520243001343434002424
6221512035134034125
711335003633143041
oct1113422503263505
9167854378221528
1040375193265989
1111957029023aaa
124640b96648945
13196b49773976a
149d8253c43021
154a03b88bbe5e
hex24b8950d6745

40375193265989 has 2 divisors, whose sum is σ = 40375193265990. Its totient is φ = 40375193265988.

The previous prime is 40375193265943. The next prime is 40375193265991. The reversal of 40375193265989 is 98956239157304.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21308914680964 + 19066278585025 = 4616158^2 + 4366495^2 .

It is a cyclic number.

It is not a de Polignac number, because 40375193265989 - 28 = 40375193265733 is a prime.

Together with 40375193265991, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40375193265919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20187596632994 + 20187596632995.

It is an arithmetic number, because the mean of its divisors is an integer number (20187596632995).

It is a 1-persistent number, because it is pandigital, but 2⋅40375193265989 = 80750386531978 is not.

Almost surely, 240375193265989 is an apocalyptic number.

It is an amenable number.

40375193265989 is a deficient number, since it is larger than the sum of its proper divisors (1).

40375193265989 is an equidigital number, since it uses as much as digits as its factorization.

40375193265989 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 440899200, while the sum is 71.

The spelling of 40375193265989 in words is "forty trillion, three hundred seventy-five billion, one hundred ninety-three million, two hundred sixty-five thousand, nine hundred eighty-nine".