4040000313101 has 4 divisors (see below), whose sum is σ = 4040010716604. Its totient is φ = 4039989909600.

The previous prime is 4040000313091. The next prime is 4040000313149. The reversal of 4040000313101 is 1013130000404.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 174077535076 + 3865922778025 = 417226^2 + 1966195^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4040000313101 is a prime.

It is a super-3 number, since 3×4040000313101³ (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4040000313101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4040000313001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4595720 + ... + 5403761.

It is an arithmetic number, because the mean of its divisors is an integer number (1010002679151).

Almost surely, 2^{4040000313101} is an apocalyptic number.

It is an amenable number.

4040000313101 is a deficient number, since it is larger than the sum of its proper divisors (10403503).

4040000313101 is an equidigital number, since it uses as much as digits as its factorization.

4040000313101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10403502.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 4040000313101 its reverse (1013130000404), we get a palindrome (5053130313505).

The spelling of 4040000313101 in words is "four trillion, forty billion, three hundred thirteen thousand, one hundred one".