40401131317 has 2 divisors, whose sum is σ = 40401131318. Its totient is φ = 40401131316.

The previous prime is 40401131297. The next prime is 40401131383. The reversal of 40401131317 is 71313110404.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25705388241 + 14695743076 = 160329^2 + 121226^2 .

It is a cyclic number.

It is not a de Polignac number, because 40401131317 - 2⁷ = 40401131189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40401131291 and 40401131300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40401191317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20200565658 + 20200565659.

It is an arithmetic number, because the mean of its divisors is an integer number (20200565659).

Almost surely, 2^40401131317 is an apocalyptic number.

It is an amenable number.

40401131317 is a deficient number, since it is larger than the sum of its proper divisors (1).

40401131317 is an equidigital number, since it uses as much as digits as its factorization.

40401131317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

The spelling of 40401131317 in words is "forty billion, four hundred one million, one hundred thirty-one thousand, three hundred seventeen".