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40401131423 = 91841439903
BaseRepresentation
bin100101101000000110…
…000101011110011111
310212021121212010100212
4211220012011132133
51130220142201143
630320544243035
72630114644112
oct455006053637
9125247763325
1040401131423
1116152427014
1279b631047b
133a6b1cbb33
141d53988579
1510b6d20918
hex96818579f

40401131423 has 4 divisors (see below), whose sum is σ = 40401663168. Its totient is φ = 40400599680.

The previous prime is 40401131383. The next prime is 40401131437. The reversal of 40401131423 is 32413110404.

40401131423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40401131423 - 28 = 40401131167 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40401131453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 128111 + ... + 311792.

It is an arithmetic number, because the mean of its divisors is an integer number (10100415792).

Almost surely, 240401131423 is an apocalyptic number.

40401131423 is a deficient number, since it is larger than the sum of its proper divisors (531745).

40401131423 is an equidigital number, since it uses as much as digits as its factorization.

40401131423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 531744.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 40401131423 its reverse (32413110404), we get a palindrome (72814241827).

The spelling of 40401131423 in words is "forty billion, four hundred one million, one hundred thirty-one thousand, four hundred twenty-three".

Divisors: 1 91841 439903 40401131423