Base | Representation |
---|---|
bin | 101101111100011110000101… |
… | …0010110001101110101010111 |
3 | 1221222220221101110112201120011 |
4 | 1123320330022112031311113 |
5 | 410432322212024004421 |
6 | 3551305040043421051 |
7 | 151060541023101016 |
oct | 13370741226156527 |
9 | 1858827343481504 |
10 | 404135121313111 |
11 | 107851819222771 |
12 | 393b0116524787 |
13 | 14466a172433a6 |
14 | 71b235c292a7d |
15 | 31ac7368684e1 |
hex | 16f8f0a58dd57 |
404135121313111 has 2 divisors, whose sum is σ = 404135121313112. Its totient is φ = 404135121313110.
The previous prime is 404135121313109. The next prime is 404135121313171. The reversal of 404135121313111 is 111313121531404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 404135121313111 - 21 = 404135121313109 is a prime.
Together with 404135121313109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (404135121313171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202067560656555 + 202067560656556.
It is an arithmetic number, because the mean of its divisors is an integer number (202067560656556).
Almost surely, 2404135121313111 is an apocalyptic number.
404135121313111 is a deficient number, since it is larger than the sum of its proper divisors (1).
404135121313111 is an equidigital number, since it uses as much as digits as its factorization.
404135121313111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 31.
Adding to 404135121313111 its reverse (111313121531404), we get a palindrome (515448242844515).
The spelling of 404135121313111 in words is "four hundred four trillion, one hundred thirty-five billion, one hundred twenty-one million, three hundred thirteen thousand, one hundred eleven".
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