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4041413002381 is a prime number
BaseRepresentation
bin111010110011110110111…
…111001000010010001101
3112022100121000120012022011
4322303312333020102031
51012203303212034011
612332333254221221
7564660660502306
oct72636677102215
915270530505264
104041413002381
111318a5430a277
12553305054811
1323414682ca81
14dd8694457ad
15701d6a54621
hex3acf6fc848d

4041413002381 has 2 divisors, whose sum is σ = 4041413002382. Its totient is φ = 4041413002380.

The previous prime is 4041413002379. The next prime is 4041413002441. The reversal of 4041413002381 is 1832003141404.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3649494433225 + 391918569156 = 1910365^2 + 626034^2 .

It is a cyclic number.

It is not a de Polignac number, because 4041413002381 - 21 = 4041413002379 is a prime.

It is a super-2 number, since 2×40414130023812 (a number of 26 digits) contains 22 as substring.

Together with 4041413002379, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4041416002381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020706501190 + 2020706501191.

It is an arithmetic number, because the mean of its divisors is an integer number (2020706501191).

Almost surely, 24041413002381 is an apocalyptic number.

It is an amenable number.

4041413002381 is a deficient number, since it is larger than the sum of its proper divisors (1).

4041413002381 is an equidigital number, since it uses as much as digits as its factorization.

4041413002381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 4041413002381 its reverse (1832003141404), we get a palindrome (5873416143785).

The spelling of 4041413002381 in words is "four trillion, forty-one billion, four hundred thirteen million, two thousand, three hundred eighty-one".