Base | Representation |
---|---|
bin | 10010011000011010101001… |
… | …00001100101010100010100 |
3 | 12022010020120202021122122202 |
4 | 21030031110201211110110 |
5 | 20244230413424444104 |
6 | 221545151514544032 |
7 | 11341226603103533 |
oct | 1114152441452424 |
9 | 168106522248582 |
10 | 40421355312404 |
11 | 11974667322790 |
12 | 4649b1a138018 |
13 | 1972943313b21 |
14 | 9da59296231a |
15 | 4a16bb34a51e |
hex | 24c354865514 |
40421355312404 has 48 divisors (see below), whose sum is σ = 77207194409856. Its totient is φ = 18364023216000.
The previous prime is 40421355312337. The next prime is 40421355312409.
40421355312404 is nontrivially palindromic in base 10.
It is a super-2 number, since 2×404213553124042 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40421355312409) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1153132142 + ... + 1153167194.
It is an arithmetic number, because the mean of its divisors is an integer number (1608483216872).
Almost surely, 240421355312404 is an apocalyptic number.
40421355312404 is a gapful number since it is divisible by the number (44) formed by its first and last digit.
It is an amenable number.
40421355312404 is a deficient number, since it is larger than the sum of its proper divisors (36785839097452).
40421355312404 is a wasteful number, since it uses less digits than its factorization.
40421355312404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47616 (or 47614 counting only the distinct ones).
The product of its (nonzero) digits is 230400, while the sum is 38.
It can be divided in two parts, 4042135 and 5312404, that added together give a palindrome (9354539).
The spelling of 40421355312404 in words is "forty trillion, four hundred twenty-one billion, three hundred fifty-five million, three hundred twelve thousand, four hundred four".
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