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40422204131 is a prime number
BaseRepresentation
bin100101101001010110…
…011110001011100011
310212100002111201200112
4211221112132023203
51130241041013011
630323020041535
72630462031431
oct455126361343
9125302451615
1040422204131
111616330a281
127a013932ab
133a726995aa
141d566b1d51
1510b8ad458b
hex96959e2e3

40422204131 has 2 divisors, whose sum is σ = 40422204132. Its totient is φ = 40422204130.

The previous prime is 40422204127. The next prime is 40422204133. The reversal of 40422204131 is 13140222404.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40422204131 - 22 = 40422204127 is a prime.

It is a super-2 number, since 2×404222041312 (a number of 22 digits) contains 22 as substring.

Together with 40422204133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 40422204097 and 40422204106.

It is not a weakly prime, because it can be changed into another prime (40422204133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20211102065 + 20211102066.

It is an arithmetic number, because the mean of its divisors is an integer number (20211102066).

Almost surely, 240422204131 is an apocalyptic number.

40422204131 is a deficient number, since it is larger than the sum of its proper divisors (1).

40422204131 is an equidigital number, since it uses as much as digits as its factorization.

40422204131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 23.

Adding to 40422204131 its reverse (13140222404), we get a palindrome (53562426535).

The spelling of 40422204131 in words is "forty billion, four hundred twenty-two million, two hundred four thousand, one hundred thirty-one".