Base | Representation |
---|---|
bin | 111010110101011100010… |
… | …101010001000101011101 |
3 | 112022111222111222111012111 |
4 | 322311130111101011131 |
5 | 1012220244001220123 |
6 | 12333214113434021 |
7 | 565051055023141 |
oct | 72653425210535 |
9 | 15274874874174 |
10 | 4043113304413 |
11 | 1319747069367 |
12 | 5536ba56b911 |
13 | 234357b83951 |
14 | dd98b1a9221 |
15 | 70285e6790d |
hex | 3ad5c55115d |
4043113304413 has 2 divisors, whose sum is σ = 4043113304414. Its totient is φ = 4043113304412.
The previous prime is 4043113304359. The next prime is 4043113304429. The reversal of 4043113304413 is 3144033113404.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2375846138884 + 1667267165529 = 1541378^2 + 1291227^2 .
It is a cyclic number.
It is not a de Polignac number, because 4043113304413 - 229 = 4042576433501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4043113304213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021556652206 + 2021556652207.
It is an arithmetic number, because the mean of its divisors is an integer number (2021556652207).
Almost surely, 24043113304413 is an apocalyptic number.
It is an amenable number.
4043113304413 is a deficient number, since it is larger than the sum of its proper divisors (1).
4043113304413 is an equidigital number, since it uses as much as digits as its factorization.
4043113304413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 4043113304413 its reverse (3144033113404), we get a palindrome (7187146417817).
The spelling of 4043113304413 in words is "four trillion, forty-three billion, one hundred thirteen million, three hundred four thousand, four hundred thirteen".
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