Base | Representation |
---|---|
bin | 111010110110011001101… |
… | …001011101111111101111 |
3 | 112022121122012200011110102 |
4 | 322312121221131333233 |
5 | 1012224400323312401 |
6 | 12333504142301315 |
7 | 565115415622622 |
oct | 72663151357757 |
9 | 15277565604412 |
10 | 4044142010351 |
11 | 131a124809363 |
12 | 553946b8783b |
13 | 234490031aa1 |
14 | dda47a69db9 |
15 | 702e641956b |
hex | 3ad99a5dfef |
4044142010351 has 2 divisors, whose sum is σ = 4044142010352. Its totient is φ = 4044142010350.
The previous prime is 4044142010309. The next prime is 4044142010353. The reversal of 4044142010351 is 1530102414404.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4044142010351 - 230 = 4043068268527 is a prime.
It is a super-2 number, since 2×40441420103512 (a number of 26 digits) contains 22 as substring.
Together with 4044142010353, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4044142010353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2022071005175 + 2022071005176.
It is an arithmetic number, because the mean of its divisors is an integer number (2022071005176).
Almost surely, 24044142010351 is an apocalyptic number.
4044142010351 is a deficient number, since it is larger than the sum of its proper divisors (1).
4044142010351 is an equidigital number, since it uses as much as digits as its factorization.
4044142010351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 4044142010351 its reverse (1530102414404), we get a palindrome (5574244424755).
The spelling of 4044142010351 in words is "four trillion, forty-four billion, one hundred forty-two million, ten thousand, three hundred fifty-one".
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