Base | Representation |
---|---|
bin | 111010110110011001110… |
… | …001111000000001011111 |
3 | 112022121122100211010110011 |
4 | 322312121301320001133 |
5 | 1012224401404322421 |
6 | 12333504301424051 |
7 | 565115443431601 |
oct | 72663161700137 |
9 | 15277570733404 |
10 | 4044144214111 |
11 | 131a125a84051 |
12 | 55394786b027 |
13 | 234490623ba1 |
14 | dda48081171 |
15 | 702e67024e1 |
hex | 3ad99c7805f |
4044144214111 has 2 divisors, whose sum is σ = 4044144214112. Its totient is φ = 4044144214110.
The previous prime is 4044144214067. The next prime is 4044144214157. The reversal of 4044144214111 is 1114124414404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4044144214111 - 229 = 4043607343199 is a prime.
It is a super-3 number, since 3×40441442141113 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4044144214171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2022072107055 + 2022072107056.
It is an arithmetic number, because the mean of its divisors is an integer number (2022072107056).
Almost surely, 24044144214111 is an apocalyptic number.
4044144214111 is a deficient number, since it is larger than the sum of its proper divisors (1).
4044144214111 is an equidigital number, since it uses as much as digits as its factorization.
4044144214111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8192, while the sum is 31.
Adding to 4044144214111 its reverse (1114124414404), we get a palindrome (5158268628515).
The spelling of 4044144214111 in words is "four trillion, forty-four billion, one hundred forty-four million, two hundred fourteen thousand, one hundred eleven".
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